find distance only section 5 Practice Questions Answers Test with Solutions & More Shortcuts
direction & distance sense test PRACTICE TEST [15 - EXERCISES]
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
Question : 11
A person starts from point T in east direction. Walks 6 m and turns right. Next walks 4 m and turns left. Next walks 3m and turns right. Now cycles for 8 km and stops. Find his distance from T.
a) $2√31 m$
b) 15 m
c) 17 m
d) $7√21 m$
e) 12 m
Answer »Answer: (b)
Distance = $√[(6+3)^2 + (4+8)^2 ] = 15 m$
Question : 12 [SSC Graduate Level Tier-I 2013]
A man travels 4 km due north, then travels 6 km due east and further travels 4 km due north. How far he is from the starting point ?
a) 10 km
b) 14 km
c) 8 km
d) 6 km
Answer »Answer: (a)
Required distance
AD = $√{DE^2 + AE^2}$
= $√{8^2 + 6^2}$
= $√{64+ 36}$
= $√{100}$ = 10 km
Question : 13
Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position ?
a) 20
b) 10
c) 0
d) 40
Answer »Answer: (b)
The movements of Kashish are as shown in Figure.
(A to b, B to C, C to D, D to E)
∴ Kashish's distance from his original position
A = AE = (AB - BE) = (AB - CD)
= (30 - 20) = 10m.
Question : 14 [SSC CHSL LDC, DEO & PA/SA 2015]
Karthik travelled 3 km east, then took a right turn and travelled 4 kms. How far is he from starting point ?
a) 12 kms
b) 7 kms
c) 5 kms
d) 3 kms
Answer »Answer: (c)
Required distance
AC = $√{AB^2 + BC^2}$
= $√{3^2 + 4^2}$
= $√{9 + 16}$
= $√{25}$
= 5 km
Question : 15 [SSC Delhi Police SI 2014]
A postman starts delivering letters 3 km southwards and then turns right. He covers 4 km on this road and again turns right. He delivers letters for 3 km and completes his daily beat. Then, he turns left for lunch at home, which is 5 km away. How far has he to travel to reach the post-office after lunch ?
a) 10 km
b) 8 km
c) 15 km
d) 9 km
Answer »Answer: (c)
Required distance
= AE = AD + DE
= 4 km + 5 km = 9 km
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